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C program to convert number in word

In this program, you will take integer input from users and you will convert the integer into a word. For example, you will take input 1234, the output will be one two three four.

#include<stdio.h>
int main()
{
    long int n=0,rev=0,rmd,i=0;
    printf("enter the number:");
    scanf("%d",&n);
    while(n!=0)
    {
    rmd=n%10;
    n/=10;
    i+=1;
    rev=rev*10+rmd;
    }
    while(i)
    {
        rmd=0;
        rmd=rev%10;
        rev=rev/10; 
        i--;
        printf(" ");
        switch(rmd)
        {
            case 0:
                printf("zero");
                break;
            case 1:
                printf("one");
                break;
            case 2:
                printf("two");
                break;
            case 3:
                printf("three");
                break;
            case 4:
                printf("four");
                break;
            case 5:
                printf("five");
                break;
            case 6:
                printf("six");
                break;
            case 7:
                printf("seven");
                break;
            case 8:
                printf("eight");
                break;
            case 9:
                printf("nine");
                break;
        }
    }
    return 0;
}

output

enter the number:1000
one zero zero zero

Working of numbers to word conversion

In this program, you will take integer input from the user and store it in a variable n.
In the outer while loop, you will reverse the number and store it in variable rev i.e rev=rev*10+rmd, and count the number of digits in an input number by incrementing the value of i.
For example, if the user enters the number 123 then after reversing the number, the number becomes 321 and i value becomes 3.
in the inner while loop, you will find a reminder of the rev number.
in the first iteration, when i=3 you will find a reminder of the rev number and stored reminder in variable rmd i.e reminder of 321 is 1, divide rev=rev/10 and rev become 32, now you will pass rmd i.e 1 in the switch case, in the switch case, case 1 will get executed and 'one' will get printed.
when i=2, a reminder of 32 is 2, divide rev=rev/10 and rev become 3, now you will pass rmd i.e 2 in the switch case, in the switch case, case 2 will get executed and 'two' will get printed.
when i=1, a reminder of 3 is 3, divide rev=rev/10 and rev become 0, now you will pass rmd i.e 3 in the switch case, in the switch case, case 3 will get executed and 'three' will get printed.
when i=0, while loop gets a break.

Dry run of numbers to a word conversion program

input i.e n=123
in outer while loop
rmd=3 , n=12 rev=3, i=1
rmd=2, n=1 rev=32, i=2
rmd=1, n=0, rev=321, i=3

in inner while loop,
reminder of rev i.e 321
rev=321
i=3, rev=321, rmd=1 print 'one'
i=2, rev=32, rmd=2 print 'two'
i=1, rev=3, rmd=3 print 'three'

input:123
output: one two three

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