In this example, you will write the c++ program to check whether the number entered by the user is even or odd.
When the number is completely divisible by 2 and the remainder is zero then the number is even. for example, 2, 4, 6, 8, 10, 12, 14, 16, 18, 20, etc are even number.
when a number is not divisible by 2 and has some remainder then the number is called an odd number. for example, 1, 3, 5, 7, 9, 11, 13, etc are odd number.
#include <iostream>
using namespace std;
int main() {
int num;
cout << "Enter the number: ";
/* take input from user */
cin >> num;
if ( num % 2 == 0)
cout << num << " is even";
else
cout << num << " is odd";
return 0;
}
Enter the number: 12 12 is even
Enter the number: 11 11 is odd
In the program, we have taken the integer number from the user and stored it in the variable num.
when if-statement is evaluated true i.e (num % 2) then print an even number and if not true, else part will get executed and print not even.
In this program, we have used a ternary operator for finding even or odd instead of if-else.
#include <iostream>
using namespace std;
int main() {
int num;
cout << "Enter the number: ";
cin >> num;
// ternary operator
(num % 2 == 0) ? cout << num << " is even" : cout << num << " is odd";
return 0;
}
Enter the number: 4 4 is even
In this example, we have used class for determining even or odd
#include<iostream>
using namespace std;
class StudyFame {
private:
int num;
public:
void getData();
void EvenOdd();
};
void StudyFame::getData() {
cout << "Enter the number: ";
cin >> num;
};
void StudyFame::EvenOdd() {
if ( num % 2 == 0)
cout << num << " is even";
else
cout << num << " is odd";
};
int main() {
StudyFame s;
s.getData();
s.EvenOdd();
return 0;
}
Enter the number: 10 10 is even
Time Complexity of all above program is: O(1)