Leap year program in PHP
In this program, you will check whether the given year is a leap year or not using if-else condition
<?php
$year=2020;
if(($year%4)==0)
{
if(($year%100)==0)
{
if(($year%400)==0)
{
echo "$year is a leap year";
}
else{
echo "$year is not a leap year";
}
}
else{
echo "$year is a leap year";
}
}
else{
echo "$year is not a leap year";
}
?>output
2020 is a leap year
Program to check leap year or not by using HTML form
In this program, you will take year input from user in HTML form and you will find whether year enter by user is leap year or not.
<!DOCTYPE html>
<html lang="en">
<head>
<title>check year is leap year or not</title>
</head>
<body>
<form>
<label> Enter the Year </label> <input type="number" name="LeapYear">
<input type="submit" value="submit" name="submitForm"></br></br>
</form>
</body>
</html>
<?php
if(isset($_GET["submitForm"]))
{
$year=$_GET['LeapYear'];
if(($year%4)==0)
{
if(($year%100)==0)
{
if(($year%400)==0)
{
echo "$year is a leap year";
}
else{
echo "$year is not a leap year";
}
}
else{
echo "$year is a leap year";
}
}
else{
echo "$year is not a leap year";
}
}
?>output
